In the given reaction sequence,identify the final product $C$:
$CH_2=CH-CH=CH_2$ $\xrightarrow{HCl, 40^{\circ}C} A$ $\xrightarrow{HI} C$
(Note: The reaction proceeds via electrophilic addition to a conjugated diene.)

$CH_3-CH=CH_2 + NOCl \rightarrow P$
Identify the adduct.

$Ph-CH_2-CH(Br)-CH_2-CH_3 \xrightarrow{NaNH_2} (A)$
Total number of elimination products are (includes stereoisomers):

Which process converts olefins into paraffins?

Which alkene on ozonolysis gives $CH_3CH_2CHO$ and $CH_3COCH_3$?

The reaction of $4$-methyloct$-1-$ene $(P, 2.52 \ g)$ with $HBr$ in the presence of $(C_6H_5CO_2)_2O_2$ gives two isomeric bromides in a $9:1$ ratio,with a combined yield of $50 \%$. Of these,the entire amount of the primary alkyl bromide was reacted with an appropriate amount of diethylamine followed by treatment with aqueous $K_2CO_3$ to give a non-ionic product $S$ in $100 \% $ yield. The mass (in $mg$) of $S$ obtained is. . . . . . . [Use molar mass (in $g \ mol^{-1}$) : $H=1, C=12, N=14, Br=80$]